The effect of columns differential height
 Figure 5.1.4-1: Frame of common practice, project <B_514>
			
				Figure 5.1.4-1: Frame of common practice, project <B_514>	Figure 5.1.4-1: Frame of common practice, project <B_514>
 Figure 5.1.4-2: 89% of the seismic force is carried by the "short" column.
			
				Figure 5.1.4-2: 89% of the seismic force is carried by the "short" column.	Figure 5.1.4-2: 89% of the seismic force is carried by the "short" column.
 Figure 5.1.4-3: The bending moment of the "short" column is four times higher than the corresponding moment of the "tall" one.
			
				Figure 5.1.4-3: The bending moment of the "short" column is four times higher than the corresponding moment of the "tall" one.	Figure 5.1.4-3: The bending moment of the "short" column is four times higher than the corresponding moment of the "tall" one.
		I.e. 89% of the seismic shear is carried from the first (short) column.	
		Example 5.1.4: 		Consider the typical columns 400/400, and seismic acceleration factor 		a		/		g		=0.10.	
		Total horizontal force: 		H		=		2·(0.10·800kN)=		160 		kN	
		Va=160		·8		/9=142.2 kN, Vb=160		·1		/9=17.8 kN	
		Ma1=-Ma2=142.2·3.0/2=213.3 kNm, Mb1=-Mb2=17.8·6.0/2=53.4 kNm	
		Left column stiffness:		 Ka=12EI/h3=		31.10·106 		N		/		m	
		Right column stiffness: 		Kb=1.5E		·		I/h3=(1.5·		31.10·106		N		/		m		)/12		=3.89		·		106 N/		m	
		therefore 		δ		=		H		/		Σ		(K)=160·103N/(34.99		·		106 N/m) =4.573 		mm		.	
		Frame of common practice:	
		In project <B_514> of the related software, the cross-section of the left column C1 and the right column C2 are 400/400 and 800/400 respectively.		Their heights are 3.00 m and 6.00 m respectively. The flanged beam cross-section is 250/500/1010/150 and its span is 5.00 m.	
									|  Figure 5.1.4-4: Elastic line, δmax=6.468 mm Figure 5.1.4-4: Elastic line, δmax=6.468 mm |  Figure 5.1.4-5: Shear force diagrams Figure 5.1.4-5: Shear force diagrams | 
										|  Figure 5.1.4-6: Bending moment diagrams Figure 5.1.4-6: Bending moment diagrams |  Figure 5.1.4-7: Axial force diagrams Figure 5.1.4-7: Axial force diagrams | 
						
				Modelling of the example with actual fixity degrees on columns i.e. those derived from the structural analysis.	
It should be noted that the actual displacement δ=6.468 mm of the crossbar is somewhat higher than the theoretical value δ		=4.573 mm assuming fixed end conditions. This is due to the regular cross-section of columns and mainly to the small stiffness of the right		column being considerably higher.	
		The actual stiffness of C1 is Ka=Va/δ=(134.3·103N)/0.006468m=20.73·106 kN/m		(against 31.10·106 N/m of the fixed-ended column).	
		The actual stiffness of C2 is Kb=Vb/δ=(25.7·103N)/0.006468m=3.97·106 kN/m		(against 3.89·106 N/m of the fixed-ended column, i.e. practically the same).	
Taking into account the shear effect (Shear effect=ON), the resulting displacement is equal to δ=6.634 mm (against δ		=6.468 mm, i.e. the shear effect is minimum).