« Estimation of the concrete’s quantity Estimation of the spacers’ quantity »

Estimation of the formworks’ quantity

In constructional works, it is common practice to pay the technicians responsible for the form-work implementation, based upon the quantity (in m3) of casted concrete. However, the most proper way is to separate those two things therefore, the following pages regard the estimation of the required moulds.

Ground floor

 Beams – Slabs m2 m2 S1: 3,80 x 5,00 – 4 x 0,40 x 0,10 + 2 x 3,60 x 0,18 = 20,136 b1,b2: 2 x 5,00 x 0,50 + 2 x (5,00-2 x 0,40) x 0,32 + + 2 x 4,20 x 0.30 = 10,208 columns (joints): 4 x 0,40 x 0,50 + 4 x 0,40 x 0,32 + 4 x 0,10 x 0,32 = 1,440 Total = 31,784 Columns: 4 x (0,40 x 0,40 x 2,50) = 16,000

Basement

 Beams – Slabs m2 m2 S1: 4,50 x 3,90 - 4 x (0,15 x 0,15) = 17,460 b1,b2: 2 x [5,00 x 0,50 +4,20 x 0,32] +  4,20 x 0,25 = 9,788 b3: 4,40 x 0,50 + 3,60 x 0,32 +  3,60 x 0,25 = 4,252 sw5: 4,40 x 0,50 + 3,60 x 0,32 = 3,352 internal column sides 4 x 2 x 0,15 x 0,32) = 0,384 Total = 35,236 Columns: 4 x (0,40 x 0,40 x 2,50) – 2 x (0,25 x 2,50) = 14,750 Shear wall sw5: 2 x (3,60 x 2,50) = 18,000 Total = 32,750

Foundation

 m2 Footings F3,4,5: 0,50 x [5,00 + 2 x 1,00 + 0,30 x 2] = 5,85 Cb1,2: 2 x [0,70 x0,10 + 4,30 x 0,60 +  0,30 x 0,30]   2 x [0,30 x0,10 + 3,60 x 0,60 +  0,30 x 0,30] = 10,04 SF4: (3,80 + 4,40) x 0,30 + (3,60 + 4,40) x 0,30 = 4,86 Columns: 2 x 2 [0,10  x 0,30 +0,10 x 0,10] + +(4,40+3,60 ) x 0,10 = 0,96 Total = 21,71

« Estimation of the concrete’s quantity Estimation of the spacers’ quantity »