« Quantity surveying Estimation of the formworks’ quantity » Estimation of the concrete’s quantity Ground floor Beams – Slabs S1: 4,40 x 5,00 x 0,18 = 3,96 b1,b2: 2 x [(5,00-2 x 0,40) x 0,30 x 0,32] = 0,81 K1,2,3,4 (part of the joint area): 4 x (0,40 x 0,40 x 0,32) = 0,20 Total= 4,97 m3 Columns C1,2,3,4: 4 x (0,40 x 0,40 x 2,50) = 1,60 m3 Basement Beams – Slabs S1: 4,40 x 5,00 x 0,18 = 3,96 b1,b2: 2 x [(5,00-2 x 0,40) x 0,25 x 0,32] = 0,67 b3,sw5: 2 x [(4,40-2 x 0,40) x 0,25 x 0,32] = 0,58 C1,2,3,4 (part of the joint area): 4 x (0,40 x 0,32) = 0,20 Total = 5,41 m3 Columns C1,2,3,4: 4 x (0,40 x 0,40 x 2,50) = 1,60 m3 SW5: 3,60 x 0,25 x 2,50 = 2,25 Total = 3,85 m3 Foundation Footings F3,4,5: 2 x (1,00 x 1,00 x 0,50) +3,00 x 0,85 x 0,50 = 2,275 CB1,2: 2 x (3,60 x 0,30 x 0,60) + (2 x 0,30 x 0,10 x 0,30) + + 2 x (0,30 x 0,30 x 0,30) = 1,368 SF: 4,40 x 1,00 x 0,30 + 4,40 x 0,30 x 0,30 = 1,716 Columns (additional volume due to foundation depth equal to 0,60 m, compared to the footings’ depth which is 0,50m): 4 x (0,40 x 0,40 x 0,10) + 3,60 x 0,25 x 0,10 = 0,154 (2 x 0,10 x 0,10 x 0,20 = 0,004) Sum = 5,51 m3 « Quantity surveying Estimation of the formworks’ quantity »