« Quantity surveying Estimation of the formworks’ quantity »

 

Estimation of the concrete’s quantity

Ground floor

Beams – Slabs

S1: 4,40 x 5,00 x 0,18 = 3,96

b1,b2: 2 x [(5,00-2 x 0,40) x 0,30 x 0,32] = 0,81

K1,2,3,4 (part of the joint area): 4 x (0,40 x 0,40 x 0,32) = 0,20

Total= 4,97 m3

Columns

C1,2,3,4: 4 x (0,40 x 0,40 x 2,50) = 1,60 m3

Basement

Beams – Slabs

S1: 4,40 x 5,00 x 0,18 = 3,96

b1,b2: 2 x [(5,00-2 x 0,40) x 0,25 x 0,32] = 0,67

b3,sw5: 2 x [(4,40-2 x 0,40) x 0,25 x 0,32] = 0,58

C1,2,3,4 (part of the joint area): 4 x (0,40 x 0,32) = 0,20

Total = 5,41 m3

Columns

C1,2,3,4: 4 x (0,40 x 0,40 x 2,50) = 1,60 m3

SW5: 3,60 x 0,25 x 2,50 = 2,25

Total = 3,85 m3

Foundation

Footings F3,4,5:

2 x (1,00 x 1,00 x 0,50) +3,00 x 0,85 x 0,50 = 2,275

CB1,2:

2 x (3,60 x 0,30 x 0,60) + (2 x 0,30 x 0,10 x 0,30) +

+ 2 x (0,30 x 0,30 x 0,30) = 1,368

SF: 4,40 x 1,00 x 0,30 + 4,40 x 0,30 x 0,30 = 1,716

Columns (additional volume due to foundation depth equal to

0,60 m, compared to the footings’ depth which is 0,50m):

4 x (0,40 x 0,40 x 0,10) + 3,60 x 0,25 x 0,10 = 0,154

(2 x 0,10 x 0,10 x 0,20 = 0,004)

Sum = 5,51 m3

 


« Quantity surveying Estimation of the formworks’ quantity »