« Estimation of the concrete’s quantity Estimation of the spacers’ quantity »

 

Estimation of the formworks’ quantity

In constructional works, it is common practice to pay the technicians responsible for the form-work implementation, based upon the quantity (in m3) of casted concrete. However, the most proper way is to separate those two things therefore, the following pages regard the estimation of the required moulds.

Ground floor

Beams – Slabs m2   m2
S1: 3,80 x 5,00 – 4 x 0,40 x 0,10 + 2 x 3,60 x 0,18 = 20,136
b1,b2: 2 x 5,00 x 0,50 + 2 x (5,00-2 x 0,40) x 0,32 +
+ 2 x 4,20 x 0.30
=
10,208
columns (joints): 4 x 0,40 x 0,50 + 4 x 0,40 x 0,32 + 4 x 0,10 x 0,32 = 1,440
  Total = 31,784
Columns:    
  4 x (0,40 x 0,40 x 2,50) = 16,000

Basement

Beams – Slabs m2   m2
S1: 4,50 x 3,90 - 4 x (0,15 x 0,15) = 17,460
b1,b2: 2 x [5,00 x 0,50 +4,20 x 0,32] +  4,20 x 0,25 = 9,788
b3: 4,40 x 0,50 + 3,60 x 0,32 +  3,60 x 0,25 = 4,252
sw5: 4,40 x 0,50 + 3,60 x 0,32        = 3,352
internal column sides 4 x 2 x 0,15 x 0,32) = 0,384
  Total = 35,236
     
Columns: 4 x (0,40 x 0,40 x 2,50) – 2 x (0,25 x 2,50) = 14,750
Shear wall sw5: 2 x (3,60 x 2,50) = 18,000
  Total = 32,750

Foundation

    m2
Footings F3,4,5: 0,50 x [5,00 + 2 x 1,00 + 0,30 x 2] = 5,85
Cb1,2: 2 x [0,70 x0,10 + 4,30 x 0,60 +  0,30 x 0,30]  
2 x [0,30 x0,10 + 3,60 x 0,60 +  0,30 x 0,30]   		= 10,04
SF4: (3,80 + 4,40) x 0,30 + (3,60 + 4,40) x 0,30 = 4,86
Columns: 2 x 2 [0,10  x 0,30 +0,10 x 0,10] +
+(4,40+3,60 ) x 0,10 		= 0,96
  Total = 21,71

 
« Estimation of the concrete’s quantity Estimation of the spacers’ quantity »